An introduction to resistors.
Posted: Mon Apr 05, 2010 3:09 pm
Welcome to the first installment to the brads projects university!
This lesson is a small introduction and one use (out of the many) for resistors.
Resistors are very handy little devices that come in a variety of packages such as:
Through hole:

Surface mount:

Dual inline package (DIP):

The most handy for prototyping is the through hole and dip type.
Resistors basically restrict current flow in a circuit. For example if we wanted to make an LED shine (without blowing it up) we would grab ourselves a battery or power supply, (lets say 6v) and then we would get an LED and a resistor.
You would connect the LED anode to the +ve end of the power supply, the cathode would goto one end of the resistor and the other end of the resistor would goto the -ve end of the battery.
A typical voltage drop of a red LED would be 2volts. So if we have 6volts total, and the LED has grabbed 2 of that, then we have 4volts left across the resistor. If the resistor that we have chosen is 1kohm (one thousand ohms) then we can work out how much current is flowing in the circuit:
4volts / 1kohms = 4mA
So in this case the LED would be quite dim.
How could we make it brighter? That's right - we would REDUCE the value of the resistor!
so lets get rid of the 1Kohm resistor and throw in a 100 ohm instead.
how much current is flowing in the circuit now?
4volts / 100ohms = 40mA
now that will be a nice and bright LED
what about if we had a blue LED with a voltage drop of 2.5volts and we wanted 25mA to flow through this LED with a power supply of 6volts.
What value resistor would we need?
This lesson is a small introduction and one use (out of the many) for resistors.
Resistors are very handy little devices that come in a variety of packages such as:
Through hole:

Surface mount:

Dual inline package (DIP):

The most handy for prototyping is the through hole and dip type.
Resistors basically restrict current flow in a circuit. For example if we wanted to make an LED shine (without blowing it up) we would grab ourselves a battery or power supply, (lets say 6v) and then we would get an LED and a resistor.
You would connect the LED anode to the +ve end of the power supply, the cathode would goto one end of the resistor and the other end of the resistor would goto the -ve end of the battery.
A typical voltage drop of a red LED would be 2volts. So if we have 6volts total, and the LED has grabbed 2 of that, then we have 4volts left across the resistor. If the resistor that we have chosen is 1kohm (one thousand ohms) then we can work out how much current is flowing in the circuit:
4volts / 1kohms = 4mA
So in this case the LED would be quite dim.
How could we make it brighter? That's right - we would REDUCE the value of the resistor!
so lets get rid of the 1Kohm resistor and throw in a 100 ohm instead.
how much current is flowing in the circuit now?
4volts / 100ohms = 40mA
now that will be a nice and bright LED

what about if we had a blue LED with a voltage drop of 2.5volts and we wanted 25mA to flow through this LED with a power supply of 6volts.
What value resistor would we need?